上 ab bc ca=0 find 1/a2-bc 1/b2-c1/c2-ab 229240-A b c 2 formula

Web 1 Look at the figures Then, fill in the blanks a) The area of Figure J is (1) square centimetres b) The area of Figure K is b) square centimetres c) The area of Figure

A b c 2 formula-WebIf three distinct real number a, b and c satisfy a 2 (a p) = b 2 (b p) = c 2 (c p) where p belongs to R ,then value of bccaab isWebIf abbcca= 0, then the value of 1 a2−bc 1 b2−ca 1 c2−ab will be A −1 B abc C abc D 0 Solution Correct option is D 0 Given abbcca= 0 Therefore, ⇒ ab= −(bcca) (i)

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WebIf a b c = 0 and a2 b2 c2 = ab bc ac, then it follows that 0 = (a b c)2 = a2 b2 c2 2(ab bc ac), or a2 b2 c2 = −2(ab bc ac) Put this together and we will see that inWebGiven, a 2b 2c 2=1We know that, (abc) 2≥0⇒a 2b 2c 22(abbcca)≥0⇒12(abbcca)≥0⇒abbcca≥ 2−1Again, (b−c) 2(c−a) 2(a−b)

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